The derivative of f(x)=5x3+2x2−x+7f(x) = 5x^3 + 2x^2 - x + 7f(x)=5x3+2x2−x+7 is:
f′(x)=15x2+4x−1f'(x) = 15x^2 + 4x - 1f′(x)=15x2+4x−1
To find the derivative of the function:
f(x)=5x3+2x2−x+7f(x) = 5x^3 + 2x^2 - x + 7f(x)=5x3+2x2−x+7
we differentiate each term separately:
ddx(5x3)=15x2\frac{d}{dx} (5x^3) = 15x^2dxd(5x3)=15x2ddx(2x2)=4x\frac{d}{dx} (2x^2) = 4xdxd(2x2)=4xddx(−x)=−1\frac{d}{dx} (-x) = -1dxd(−x)=−1ddx(7)=0\frac{d}{dx} (7) = 0dxd(7)=0
So, the derivative is: